\u0110\u00e3 l\u00e0 d\u00e2n \u201ctrong ng\u00e0nh\u201d s\u1ed1 \u0111\u1ec1 th\u00ec ai c\u0169ng bi\u1ebft kh\u00e1i ni\u1ec7m l\u00f4 khung 3 ng\u00e0y. \u0110\u00e2y l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p \u201cd\u1eaft t\u00fai\u201d c\u1ee7a t\u1ea5t c\u1ea3 nh\u1eefng ng\u01b0\u1eddi ch\u01a1i l\u00e2u n\u0103m. Th\u1ef1c t\u1ebf, n\u1ebfu bi\u1ebft c\u00e1ch v\u00e0o ti\u1ec1n, \u00e1p d\u1ee5ng c\u00e1ch soi c\u1ea7u h\u1ee3p l\u00fd th\u00ec % th\u1eafng khi theo ph\u01b0\u01a1ng ph\u00e1p n\u00e0y l\u00e0 r\u1ea5t cao. Mu\u1ed1n hi\u1ec3u r\u00f5 h\u01a1n v\u1ec1 v\u1ea5n \u0111\u1ec1 n\u00e0y h\u00e3y nghi\u00ean c\u1ee9u nh\u1eefng th\u00f4ng tin cung c\u1ea5p d\u01b0\u1edbi \u0111\u00e2y.<\/p>\n
1. L\u00f4 khung 3 ng\u00e0y l\u00e0 g\u00ec?<\/h2>\n
\u0110\u00e2y l\u00e0 m\u1ed9t kh\u00e1i ni\u1ec7m r\u1ea5t r\u1ed9ng l\u1edbn. L\u00fd do l\u00e0 n\u00f3 bao g\u1ed3m r\u1ea5t nhi\u1ec1u lo\u1ea1i khung 3 ng\u00e0y \u0111i k\u00e8m. V\u00ec v\u1eady \u0111\u1ec3 \u0111i s\u00e2u chi ti\u1ebft th\u00ec h\u00e3y hi\u1ec3u r\u00f5 c\u00e1c h\u00ecnh th\u1ee9c nu\u00f4i khung 3 ng\u00e0y.<\/p>\n
Kh\u00e1i ni\u1ec7m<\/h3>\n
L\u00f4 khung nu\u00f4i 3 ng\u00e0y th\u1ef1c ch\u1ea5t l\u00e0 m\u1ed9t ph\u01b0\u01a1ng ph\u00e1p ch\u01a1i quen thu\u1ed9c v\u1edbi d\u00e2n nu\u00f4i s\u1ed1 h\u1ecdc. C\u00e1ch ch\u01a1i \u0111\u01a1n gi\u1ea3n, m\u1ed7i ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra m\u1ed9t d\u00e0n v\u1edbi c\u00e1c con s\u1ed1 \u0111\u1ec3 ch\u01a1i trong th\u1eddi gian l\u00e0 3 ng\u00e0y li\u00ean ti\u1ebfp. T\u00f9y theo lo\u1ea1i c\u1ea7u s\u1ebd quy\u1ebft \u0111\u1ecbnh ch\u01a1i ti\u1ebfp hay d\u1eebng l\u1ea1i sau 3 ng\u00e0y. V\u00ed d\u1ee5, b\u1ea1n ch\u1ecdn d\u00e0n v\u1edbi con 45, 24, b\u1ea1n s\u1ebd ghi \u0111i\u1ec3m trong 3 ng\u00e0y v\u1edbi 2 con n\u00e0y m\u00e0 kh\u00f4ng thay \u0111\u1ed5i. Trong gi\u1edbi l\u00f4 \u0111\u1ec1 c\u00f3 3 h\u00ecnh th\u1ee9c nu\u00f4i l\u00f4 khung max 3 ng\u00e0y. \u0110\u00f3 l\u00e0 b\u1ea1ch th\u1ee7, song th\u1ee7 v\u00e0 cu\u1ed1i c\u00f9ng l\u00e0 d\u00e0n l\u00f4.<\/p>\n
B\u1ea1ch th\u1ee7 l\u00f4 khung 3 ng\u00e0y<\/h3>\n
V\u1edbi h\u00ecnh th\u1ee9c n\u00e0y, anh em s\u1ebd ch\u1ecdn 1 con \u0111\u1eb9p nh\u1ea5t \u0111\u1ec3 b\u1ea1ch th\u1ee7 v\u1edbi 2 con s\u1ed1. Khi \u0111\u00e3 c\u00f3 con s\u1ed1 th\u00ec anh em s\u1ebd ghi \u0111i\u1ec3m t\u1ea1i n\u01a1i ch\u01a1i uy t\u00edn v\u1edbi s\u1ed1 \u0111i\u1ec3m theo nhu c\u1ea7u.<\/p>\n
C\u00e1ch ch\u01a1i n\u00e0y \u0111\u01b0\u1ee3c khuy\u00ean v\u00e0o ti\u1ec1n theo 2 d\u1ea1ng t\u1ef7 l\u1ec7 (s\u1ebd chia s\u1ebb ph\u00eda d\u01b0\u1edbi). V\u00e0o th\u1ebf n\u00e0o th\u00ec hi\u1ec7u su\u1ea5t h\u00f4m sau ph\u1ea3i g\u1ea5p 1.5 l\u1ea7n h\u00f4m tr\u01b0\u1edbc. V\u00ed d\u1ee5, ch\u1ecdn con 12 \u0111\u1ec3 nu\u00f4i trong 3 ng\u00e0y. \u0110\u1ec3 nu\u00f4i l\u00f4 b\u1ea1ch th\u1ee7 khung 3 ng\u00e0y, m\u1ed7i ng\u00e0y b\u1ea1n s\u1ebd \u0111\u00e1nh con 12 n\u00e0y v\u1edbi m\u1ed9t s\u1ed1 \u0111i\u1ec3m kh\u00e1c nhau.<\/p>\n
Song th\u1ee7 l\u00f4 khung 3 ng\u00e0y<\/h3>\n
C\u00e1ch ch\u01a1i n\u00e0y kh\u00f4ng c\u00f3 nhi\u1ec1u \u0111i\u1ec3m kh\u00e1c bi\u1ec7t v\u1edbi l\u00f4 b\u1ea1ch th\u1ee7 khung 3 ng\u00e0y. Thay v\u00ec ch\u1ecdn 1 c\u1eb7p 2 ch\u1eef s\u1ed1, th\u00ec s\u1ebd ch\u1ecdn 2 c\u1eb7p 2 ch\u1eef s\u1ed1 nu\u00f4i 3 ng\u00e0y. M\u1ed9t bi\u1ebfn th\u1ec3 kh\u00e1c c\u1ee7a song th\u1ee7 khung 3 ng\u00e0y ch\u00ednh l\u00e0 d\u1ea1ng k\u00e9p.<\/p>\n
Nu\u00f4i khung 3 ng\u00e0y d\u00e0n l\u00f4<\/h3>\n
V\u1edbi c\u00e1ch nu\u00f4i l\u00f4 3 ng\u00e0y n\u00e0y, anh em s\u1ebd ch\u1ecdn t\u1ed1i thi\u1ec3u l\u00e0 3 con. C\u01a1 h\u1ed9i tr\u00fang khi \u0111\u00e1nh nhi\u1ec1u con s\u1ebd cao h\u01a1n l\u00e0 \u0111\u00e1nh 1 ho\u1eb7c 2 con. Tuy nhi\u00ean, anh em s\u1ebd ph\u1ea3i b\u1ecf ra s\u1ed1 v\u1ed1n nhi\u1ec1u h\u01a1n. H\u00ecnh th\u1ee9c n\u00e0y ch\u1ec9 c\u00f3 th\u1ec3 th\u1eafng cao khi b\u1ea3n th\u00e2n ng\u01b0\u1eddi ch\u01a1i bi\u1ebft c\u00e1ch v\u00e0o ti\u1ec1n chu\u1ea9n.<\/p>\n
Nu\u00f4i l\u00f4 k\u00e9p khung 3 ng\u00e0y<\/h3>\n
\u0110\u01b0\u1ee3c hi\u1ec3u l\u00e0 nu\u00f4i d\u00e0n v\u1edbi nh\u1eefng con trong b\u1ed9 k\u00e9p. B\u1ed9 k\u00e9p \u1edf \u0111\u00e2y l\u00e0 nh\u1eefng c\u1eb7p s\u1ed1 c\u00f3 2 s\u1ed1 gi\u1ed1ng nhau, t\u1eeb 00 cho t\u1edbi 99.<\/p>\n
<\/p>\n
2. Nu\u00f4i l\u00f4 khung 3 ng\u00e0y v\u00e0o ti\u1ec1n th\u1ebf n\u00e0o?<\/h2>\n
Mu\u1ed1n nu\u00f4i l\u00f4 khung 3 ng\u00e0y chu\u1ea9n m\u00e0 m\u00f9 m\u1edd v\u1ec1 c\u00e1ch v\u00e0o ti\u1ec1n th\u00ec anh em ch\u1ec9 c\u00f3 n\u01b0\u1edbc m\u1ea5t ti\u1ec1n oan. \u0110\u1ed1i v\u1edbi h\u00ecnh th\u1ee9c ch\u01a1i n\u00e0y, nh\u1ea5t \u0111\u1ecbnh anh em ph\u1ea3i ghi nh\u1edb c\u00e1c t\u1ef7 l\u1ec7 sau.<\/p>\n
T\u1ef7 l\u1ec7 1:2:3<\/h3>\n
V\u1edbi t\u1ef7 l\u1ec7 n\u00e0y, anh em s\u1ebd v\u00e0o ti\u1ec1n nu\u00f4i khung 3 ng\u00e0y theo \u0111\u00fang c\u00f4ng th\u1ee9c: Ng\u00e0y 1 v\u00e0o ti\u1ec1n 1 ph\u1ea7n, ng\u00e0y th\u1ee9 2 g\u1ea5p \u0111\u00f4i. T\u1edbi ng\u00e0y th\u1ee9 3 s\u1ebd ph\u1ea3i v\u00e0o ti\u1ec1n 3 ph\u1ea7n. V\u00ed d\u1ee5, anh em ch\u1ecdn 1 b\u1ed9 M, ghi \u0111i\u1ec3m trong 3 ng\u00e0y theo t\u1ef7 l\u1ec7 nh\u01b0 sau:<\/p>\n
Ng\u00e0y 1: Ch\u01a1i n \u0111i\u1ec3m => M\u1ea5t n x 23.000\u0111 => Tr\u00fang: n x 80.000\u0111, tr\u01b0\u1ee3t s\u1ebd m\u1ea5t n x 23.000\u0111.<\/p>\n
Ng\u00e0y 2: Ch\u01a1i 2n \u0111i\u1ec3m => M\u1ea5t 2n x 23.000\u0111 => Tr\u00fang \u0103n 91n, tr\u01b0\u1ee3t s\u1ebd m\u1ea5t 3n x 23n<\/p>\n
Ng\u00e0y 3: Ch\u01a1i 3n \u0111i\u1ec3m => M\u1ea5t 3n x 23.000\u0111 => Tr\u00fang \u0103n 102n, tr\u01b0\u1ee3t h\u1ebft c\u1ea7u.<\/p>\n
T\u1ef7 l\u1ec7 1:3:10<\/h3>\n
T\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1ch v\u00e0o ti\u1ec1n tr\u00ean, ch\u1ec9 kh\u00e1c \u1edf t\u1ef7 l\u1ec7. Th\u01b0\u1eddng \u00e1p d\u1ee5ng v\u1edbi nh\u1eefng anh em nu\u00f4i song th\u1ee7 ho\u1eb7c d\u00e0n 3 ng\u00e0y. T\u1ef7 l\u1ec7 \u0103n truy\u1ec1n th\u1ed1ng g\u1ea7n 3.5, v\u00ec v\u1eady n\u1ebfu \u0103n 1 \u0111i\u1ec3m th\u00ec anh em c\u00f3 th\u1ec3 nu\u00f4i \u0111\u01b0\u1ee3c 3.5 con. V\u1edbi c\u00e1ch t\u00ednh n\u00e0y, n\u1ebfu ch\u01a1i b\u1ed9 d\u01b0\u1edbi 4 con th\u00ec b\u1ebft b\u00e1t nh\u1ea5t v\u1eabn l\u00e0 h\u00f2a ti\u1ec1n. M\u1ed7i con s\u1ebd t\u00ednh ri\u00eang \u0111i\u1ec3m.<\/p>\n
Ng\u00e0y 1: 1 con ghi n \u0111i\u1ec3m => M\u1ea5t 2n x 23.000\u0111 => Tr\u00fang 1 con \u0111\u01b0\u1ee3c 34n, tr\u00fang 2 con \u0103n 114n. Tr\u01b0\u1ee3t m\u1ea5t 2n x 23.<\/p>\n
Ng\u00e0y 2: 3n cho t\u1eebng con m\u1ed9t, m\u1ea5t 6n x 23.000\u0111. Tr\u00fang 1 con \u0103n 56n, tr\u00fang 2 con \u0103n 296n. Tr\u01b0\u1eddng h\u1ee3p tr\u01b0\u1ee3t m\u1ea5t 8n x 23.<\/p>\n
Ng\u00e0y 3: M\u1ed7i con ghi 10 \u0111i\u1ec3m, m\u1ea5t 20n x 23. Tr\u00fang 1 con \u0103n 156n, tr\u00fang 2 con \u0103n 956n.<\/p>\n
L\u01b0u \u00fd khi nu\u00f4i l\u00f4 khung 3 ng\u00e0y<\/h3>\n
Mu\u1ed1n nu\u00f4i khung l\u00f4 3 ng\u00e0y th\u00ec ngo\u00e0i vi\u1ec7c hi\u1ec3u c\u01a1 b\u1ea3n, n\u1eafm \u0111\u01b0\u1ee3c t\u1ef7 l\u1ec7 v\u00e0o ti\u1ec1n th\u00ec anh em c\u0169ng ph\u1ea3i \u0111\u1ec3 t\u00e2m t\u1edbi m\u1ed9t s\u1ed1 \u0111i\u1ec1u sau:<\/p>\n
C\u1ea7n \u0111\u1ea7u t\u01b0 th\u1eddi gian nghi\u00ean c\u1ee9u c\u1ea7u l\u00f4<\/p>\n
K\u1ebft h\u1ee3p linh ho\u1ea1t, \u0111a d\u1ea1ng ph\u01b0\u01a1ng ph\u00e1p soi c\u1ea7u l\u00f4 khung 3 ng\u00e0y \u0111\u1ec3 t\u0103ng c\u01a1 h\u1ed9i v\u00e0o b\u1edd an to\u00e0n.<\/p>\n
Nu\u00f4i song l\u00f4 th\u1ee7 3 ng\u00e0y th\u01b0\u1eddng ch\u1ec9 ph\u00f9 h\u1ee3p v\u1edbi 1, 2 c\u1eb7p song ho\u1eb7c b\u1ea1ch th\u1ee7 c\u0169ng nh\u01b0 l\u00f3t.<\/p>\n
N\u1ebfu c\u00e2n \u0111\u1ed1i, chia ti\u1ec1n t\u1ed1t th\u00ec c\u00f3 th\u1ec3 c\u00e2n nh\u1eafc nu\u00f4i ch\u1ed3ng l\u00f4 khung.<\/p>\n
Ch\u1ec9 nu\u00f4i trong 3 ng\u00e0y, kh\u00f4ng n\u00ean theo l\u00e2u. Qu\u00e1 th\u1eddi gian n\u00e0y kh\u00f4ng v\u1ec1 th\u00ec b\u1ecf \u0111\u1ec3 tr\u00e1nh l\u1ed7.<\/p>\n<\/div>\n